(855) 4-ESSAYS

Type a new keyword(s) and press Enter to search

Standardization of NaOH Solution Using Oxalic Acid


             Results:.
             Pipette Solution: NaOH.
             Pipette Volume: 25ml ©Ã¸.
             Burette Solution: Oxalic acid solution.
             Indicator: Phenolphthalein.
             .
             Rough reading = 24.6 ml.
             Accurate reading 1 = 24.5 ml.
             Accurate reading 2 = 24.5 ml.
             Accurate reading 3 = 24.6 ml.
             Concordant results = (24.6+24.6+24.5+24.5)/4 .
             Average volume of Oxalic acid solution added = 24.55 ml.
             Analysis:.
             2NaOH + COOH COO-Na+ + 4H2O.
             I I.
             COOH COO Na.
             From the equation: 2M NaOH = 1M (COOH).
             No. of moles of (COOH) ©u H ©uO = Concentration of solution
             • Volume .
             I.e. no. of moles of(COOH) ©u H ©uO = .05
             • (24.55/1000).
             = 0.001275 moles.
             The number of NaOH moles must be double this value because the equatio makes the ratio out to be 1: 2.
             No. of moles of NaOH = Number of moles of (COOH) ©u H ©uO
             • 2.
             I.e. no. of moles of NaOH = ((0.001275
             • 2)
             •1000)/25.
             = .102 moles.
             .
             After analyzing the results we can use our answers to figure out the percentage error for this experiment. .
             The results indicate that the concentration of our solution of NaOH is .102M/dm ©Ã¸. However we know that the value of the NaOH solution is about .1M/dm ©Ã¸. Therefore we can work out the error in our results. .
             % Error in results = Difference in concentration The actual concentration
             • 100.
             % Error in results = (.002/.1)
             • 100.
             = 2%.
             Error Analysis:.
             Chemical balance is ¾ 0.01g, .
             Measures Value = 1.58g .
             (.01
             • ¬ 1.58)
             •100 = 0.63% .
             250ml volumetric flask is ¾ 0.25ml .
             Measures Value = 250ml.
             (.25/250)
             •100 =.0006%.
             25ml pipette ¾ 0.025ml.
             Measures Value = 25ml.
             (.025
             • ¬ 25)
             •100 = 0.001%.
             50ml burette ¾ 0.1ml.
             Measures Value = 50ml.


Essays Related to Standardization of NaOH Solution Using Oxalic Acid

1. Titration of acids and bases

An indicator solution (phenolphthalein in this experiment) is used to show when the amount of acid equals the amount of base in the solution. ... In the standardization of NaOH, thewater was not boiled. ... The unknown was then titrated with the NaOH solution. ... Also, using the data aquired the molarity of NaOH was determined (0.0999 mol/L), the standard deviation of NaOH solution was determined (1.6885 x 10 ), the average percent of KHP was determined (74.8 %) and the standard deviation of the unknown was determined (5.3611). ... An indicator solution (phenolphthalein in this experi...

  • Word Count: 911
  • Approx Pages: 4
  • Grade Level: High School

2. Acid-base titrations

In an acid-base titration either the concentration of the acid or teh base must be known, then we can use the results of the titration to find the other concentration. ... Purpose: To determine the concentration of the HCl solution using acid-bade titration and verify if the molarity is equal to 1.5 mol/L. Materials: Apparatus - standardized NaOH solution - 250 mL beakers (2) - unknown concentration of HCl solution - 50 mL burets (2) - phenolphthalein solution - double buret clamp - ring stand - 250 mL Erlenmeyer flasks (2) ...

  • Word Count: 1017
  • Approx Pages: 4
  • Grade Level: High School

3. Ionization Constant of a Weak Acid

To tie everything together, a buret was filled with NaOH, titrating an unknown weak acid solution. ... Base was added to the acid, and a magnetic stirring bar was used to evenly distribute the solution. A pH meter was used to measure pH levels of the solution. ... At the solutions highest pH, all of the weak acid's hydronium ions are being used up and is the reason why the pH finally levels off. ... Then, the pH levels off once more to a very basic level because the NaOH is using all of the weak acid's hydronium ions up. ...

  • Word Count: 1211
  • Approx Pages: 5
  • Grade Level: High School

4. Acid Rain

(Blester) The lead-acid cell uses sulfuric acid as the electrolyte. The lead-acid storage battery is the most common secondary battery used today, and is typical of those used in automobiles. ... The lead storage battery consists of two electrodes or plates, which are made of lead and lead peroxide and are immersed, in an electrolytic solution of sulfuric acid. ... At the sulfate ion that is present in the solution from the sulfuric acid. ... The amount of base needed to neutralize the lake water is: Volume of lake = 2000m x 800m x 50m = 800,000,000 m3 or 8x108 m3 Since 1m3=1000L, therefor...

  • Word Count: 2958
  • Approx Pages: 12
  • Grade Level: High School

5. Acids, Bases & Salts

Thus acids are defined as substances that release hydrogen ions in solution. ... Hydrochloric acid, like sulfuric acid, is used to clean metals. Hydrochloric acid is also used to clean brick and tile; it is used in the manufacture of sugar and glue. ... Since the formula for water can be written as HOH instead of H2O, the reaction involves single replacement: 2 Na (s) + 2 HOH (l) à 2 NaOH (aq) + H2 (g) Properties of Bases: (in water solutions) 1. ... Water solutions of calcium hydroxide, called limewater, can be used in the lab as a test for the presence of carbon dioxide. ...

  • Word Count: 2035
  • Approx Pages: 8
  • Grade Level: High School

6. acid

Acidic solutions have more H3O+ than OH- in them, while the opposite is the case for basic solutions. ... The strong base NaOH is used in many household-cleaning agents such as oven cleaner and drain clog-remover. The acidity (or basicity) of a solution is measured using the pH scale. ... Scientists use something called the "pH" scale to measure how acidic or basic a liquid is. ... Also some litmus paper turns red in acidic solutions and blue in alkaline solutions. ...

  • Word Count: 581
  • Approx Pages: 2
  • Grade Level: High School

7. The Effect of Acids and Bases on Bacterial Growth

Our alternative hypothesis (H1) is that the soil bacteria will resist the basic solution more than the acidic solution. ... Acids and bases are common solutions that exist everywhere. ... Our alternative hypothesis (H1) is that the soil bacteria will resist the basic solution more than the acidic solution. ... Acids and Bases Acids and bases used in this experiment were hydrochloric acid (HCl), and sodium hydroxide (NaOH). ... In this method, bacteria is spread along the top of the agar in the petri plate using swabs, and several paper discs dipped in the HCl and NaOH solutions, and were plac...

  • Word Count: 1221
  • Approx Pages: 5
  • Has Bibliography
  • Grade Level: High School

8. Neutralizing Acids and Bases-

Most of the experiments resulted in a pH neutral solution, except for the Sulfuric Acid and the Sodium Hydroxide. ... I decided to use Vinegar (Acetic Acid) and Baking Soda (Sodium Bicarbonate.) ... The result was a very pasty solution, that foamed, but not as much as I had expected. ... Since I only used five ml. or half the acid, I had to use .5 ml., or half the base as well. ... Chemical Name Chemical Formula Equivalency Acids Acetic Acid HC2H3O2 Vinegar Hydrogen Peroxide H2O2 Dental Rinse (Artificial Blonde) Acetylsalicylic Acid HC9H7O4 Aspirin Asc...

  • Word Count: 1198
  • Approx Pages: 5
  • Grade Level: High School

9. Water

The lead-acid cell uses sulfuric acid as the electrolyte. The lead-acid storage battery is the most common secondary battery used today, and is typical of those used in automobiles. ... The lead storage battery consists of two electrodes or plates, which are made of lead and lead peroxide and are immersed in an electrolytic solution of sulfuric acid. ... At the sulfate ion that is present in the solution from the sulfuric acid. ... The pH is: No. mol of hydrogen ions = 0.0443 mol/L x 2 = 0.0886 mol/L hydrogen ions pH = - log [H] = - log (0.0886) = - (-1.0525) = 1.05 Therefore, pH is 1.05. ii) ...

  • Word Count: 3045
  • Approx Pages: 12
  • Has Bibliography

Got a writing question? Ask our professional writer!
Submit My Question