So, we can assign the weight of hippo B to be 167 kg. .
312 kg 167 kg = 145 kg, so we assign the weight of hippo C to be 145 kg. .
356 kg 145 kg = 211 kg, so we assign the weight of hippo D to be 211 kg.
Now, we know the individual weights for each hippo, so we have answered one of the questions. .
A = 299 kg, B = 167 kg, C = 145 kg, D = 211 kg. .
We can check ourselves by adding every possible pair and comparing the answers to the weight that are given in the problem.
(A) (B) (A) (C) (A) (D).
299 kg + 167 kg = 466 kg áÌ 299 kg + 145 kg = 444 kg áÌ 299 kg + 211 kg = 510 kg .
(B) (C) (C) (D).
167 kg + 145 kg = 312 kg áÌ 145 kg + 211 kg = 356 kg áÌ.
By adding the weights of the two heaviest hippos, A and D, we can determine the weight of the pair that broke the scale.
(A) (D).
299 + 211 = 510 kg.
Now, we have answered both questions. .
In the second solution,.
1) Let the weight of one hippo be A, the weight of another hippo be B, and so forth for the weight of each hippo.
Weight of hippos = A, B, C, D.
2) Since we are given the weights for every possible pair, we could assume that the following statements are true:.
A + B = 312 kg A + C = 356 kg A + D = 378 kg.
B + C = 444 kg B + D = 466 kg C + D = heaviest pair of hippos.
3) If this is true, then we know that A and B are the lightest because combined, they are the lightest pair of the given weights. A and C is the second lightest pair, and so forth.
4) Obviously, A + B is smaller than A + C because A + B = 312 and A + C = 356.
5) The value of A remains the same in each statement above. Therefore, we know that B must be smaller than C.
