The beaker will be filled with Na S O and water via two measuring cylinders and placed on the A4 paper marked with a cross. ... Results There are two graphs behind this sheet of paper. ... And then multiplied by 10 000 to make it easier to deal with and to plot on the graph. ... I have made two graphs for the reason that the first table shows time taken for cross to be obscured and the second shows rate of reaction. There are two graphs for the first results table to show the difference in time taken and rate of reaction i.e. the time taken for cross to be obscured shows negative correlation...

• Word Count: 977
• Approx Pages: 4
• Has Bibliography
• Grade Level: High School

Once I had done the graph I realised that I had a few results were anolomisys. The shape of my graph was going up fast at first then it slowed down. Here are a few points about rates of reaction: Rates of reaction I will be comparing rates of reaction for1 minuet on my graph. The 1 minuet I will be comparing will be from 4mins -5mins. 4 Mins 39/240= 0.1625 CM3/s 4Mins20Secs 43/260= 0.1653846 Cm3/s 4Mins40Secs 47/280= 0.1678571 Cm3/s Evaluation I think my method was a suitable one although I think I could have added more Marble chips to make the rate of reaction a littl...

• Word Count: 888
• Approx Pages: 4
• Grade Level: High School

So, the equation is x amount of Sulfur produced/time which is proportional to,( 1)/(time(s)) (relative rate of reaction) so therefore the units for the rate of reaction will be s^-1. I will then put the number in standard form because it will allow me to get a manageable number which can be easily plotted on a graph once I obtain my results. Therefore the units would be s^-1 x 10^-3. ...

• Word Count: 3666
• Approx Pages: 15
• Has Bibliography
• Grade Level: High School